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To: Jonty30

The reason the astronaut cannot tell thee difference is because he/she is stretched only from the perspective of an eexternal observer. From the astronaut’s point of view the space is almost normal, aside from the distortion of the field of view.. By the time the astronaut is about able to observe a difference, thee astronaut is virtually frozen in time and thought at the same time as being disintegratedd as the space becomes dimensionless.


3 posted on 04/05/2013 6:40:15 PM PDT by WhiskeyX (The answer is very simple and easy to understand economics. The U.S. Treasury is printing vast)
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To: WhiskeyX
The reason the astronaut cannot tell thee difference is because he/she is stretched only from the perspective of an eexternal observer. From the astronaut’s point of view the space is almost normal, aside from the distortion of the field of view..

This is incorrect. The "stretching" etc. is due to tidal effects, which are no different than those responsible for the Roche limit for bodies in orbit. Inside this limit they will be disrupted by "tidal", or differential effects of gravity, even though they are in free fall.

The difference is that as one approaches a black hole, these effects become very large even over small distances. For example, if the earth were shrunk to 1/100 its radius, making it 1 million times as dense, then a pair of objects in the new LEO, would have a radial stretching tidal field of about 1 g/meter, so if they were tethered together by a 1 meter rope in the radial direction, the tension in the rope would be the same as if one of the objects were hanging by it in the real 1 g gravitational field of earth. Here's my calculation ... really!


11 posted on 04/05/2013 9:48:46 PM PDT by dr_lew
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