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Centrifugal weapon could deliver stealth firepower
New Scientist ^ | 5/11/05 | Will Knight

Posted on 05/11/2005 1:07:57 PM PDT by LibWhacker

click here to read article


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To: LibWhacker

I'd probably be better with a gun than I would a screwdriver anyway. Though I prefer margaritas. Oh wait!, that's another subject...


101 posted on 05/11/2005 2:10:53 PM PDT by PreviouslyA-Lurker (...where the spirit of the Lord is, there is liberty. 2 Corinthians 3:16-18)
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To: Doctor Stochastic

LOL


102 posted on 05/11/2005 2:10:59 PM PDT by marblehead17 (I love it when a plan comes together.)
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To: LibWhacker
Just wait, the Democrats and gun grabbers will be screaming for DREADlocks.

Molon Labe!

Garde la Foi, mes amis! Nous nous sommes les sauveurs de la République! Maintenant et Toujours!
(Keep the Faith, my friends! We are the saviors of the Republic! Now and Forever!)

LonePalm, le Républicain du verre cassé (The Broken Glass Republican)

103 posted on 05/11/2005 2:11:20 PM PDT by LonePalm (Commander and Chef)
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Comment #104 Removed by Moderator

To: JoeFromSidney

The patent is probably for a specific type of this device. There are number of ways to build something that uses this principle.


105 posted on 05/11/2005 2:11:36 PM PDT by TalonDJ
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Comment #106 Removed by Moderator

To: MeanWestTexan

The recoil you have on a normal weapon occurs as the mass you are projecting (i.e. bullet) is sped up. I would guess that the recoil in this weapon also happens as the mass is sped up. As the disc begins rotating, the force pushing back against the direction of rotation is equivalent of the force pushing back against the gun when it is fired. If the rounds were dropped into the disc after rotation has already started, the disc would experience a force opposite to its direction of rotation for each added round. This is the equivalent of recoil.

The problem with a weapon of this sort is that it has a large rotational momentum. If you tried to fire it while driving over bumps which change the axis of rotation, the top of the vehicle could be ripped entirely off if the system were not well reinforced.

This is a very revolutionary weapon. Ammunition would be lighter and cheaper because explosives would be unnecessary. The electrical power source is already built into many tanks. Accuracy is better without recoil and the speed at which mass is projected is simply incredible. One of the best advantages is that you have immediate 360 degree coverage because the ammunition can be released programmatically at any point in rotation. This means that you could give 4 gunners 4 scopes and have them all fire at a degree of rotation using the same weapon.


107 posted on 05/11/2005 2:13:16 PM PDT by Perspicac
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To: avg_freeper; Steely Tom; SlowBoat407; mnehrling

The "recoil" is angular, a torque impulse, in the opposite direction of the spin. Also, as Tom says, it occurs at load or spin-up, separated in time from the release. There would be little or no recoil at the moment of release.

There could be considerable vibration when loading, but if the projectiles distributed evenly in chambers around the circumference, there need not be a lot of vibration when loaded but not firing.


108 posted on 05/11/2005 2:13:24 PM PDT by c-five
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To: TalonDJ

Cool! I believe you guys if you've seen the math. I certainly haven't. What is the velocity of the tip of the scoop and what is the velocity of the ball as it leaves the scoop? Is it double? Or just some small percentage faster?


109 posted on 05/11/2005 2:13:25 PM PDT by LibWhacker
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To: bobbdobbs

At the moment of release, momentum is perserved by virture of the fact that neither the wheel or the ball change their momentum. The only change in momentum would come from the constant spinning of the wheel.


110 posted on 05/11/2005 2:13:35 PM PDT by Sofa King (MY rights are not subject to YOUR approval.)
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To: LibWhacker
106 posts and no one has bothered to post an illustration? Why is it me that always has to do it?


111 posted on 05/11/2005 2:13:46 PM PDT by Plutarch
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To: LibWhacker
Are you sure about that?

He's right, you've got to rememeber that the ball moves in the scoop. The ball leaves the scoop faster than the tip of the scoop is moving.

112 posted on 05/11/2005 2:15:01 PM PDT by delacoert (imperat animus corpori, et paretur statim: imperat animus sibi, et resistitur. -AUGUSTINI)
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To: bobbdobbs
Right, the wobble absorbs the recoil. If you imagine it spinning in space and you fired a projective from it the result would be and axis wobble. Clearly 'no recoil' is deceptive, but there would not be a traditional gun recoil.
113 posted on 05/11/2005 2:15:25 PM PDT by TalonDJ
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To: LibWhacker
Depends on a bunch of factors like the shape (curvature) of the scope and what not. I don't know of any 'rule of thumb'.
114 posted on 05/11/2005 2:17:21 PM PDT by TalonDJ
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Comment #115 Removed by Moderator

To: LibWhacker
""A Jai alai "high lie" ball travels faster than the scoop used to throw it.""

"Are you sure about that? "

Think about it. The scoop is rotating at some velocity, and the ball is rolling forward and outward on that scoop. The balls tangential velocity is going to be the sum of the tangential velocity of the scoop where the ball is, and the tangential velocity of the ball relative to the scoop.

It amounts to the same thing as a marble rolling down your car's hood going faster than your car.
116 posted on 05/11/2005 2:18:03 PM PDT by Born to Conserve
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Comment #117 Removed by Moderator

To: Born to Conserve
It amounts to the same thing as a marble rolling down your car's hood going faster than your car.

Okay, cool . . . That's PERFECTLY clear! Interesting, guys, thanks.

118 posted on 05/11/2005 2:21:27 PM PDT by LibWhacker
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To: Sofa King
"There is no opposing force. The mechanism that spins the bearings gives them energy; when the bearings are 'fired', they are mearly released."

And then the wheel is instantly out of balance, causing the device to recoil in the opposite direction of the released projectile.

Voila! The laws of physics are obeyed!

119 posted on 05/11/2005 2:23:53 PM PDT by nightdriver
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To: bobbdobbs

Yes, conservation of momentum always applies but a 'traditional' recoil is not based on F=MA and not conservation of momentum. So there is a reactive force it is just unlike a normal gun's recoil.


120 posted on 05/11/2005 2:24:34 PM PDT by TalonDJ
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