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Math problems too big for our brains
Ottawa Citizen via The Windsor Star ^
| November 8 2005
Posted on 11/08/2005 8:48:52 AM PST by RightWingAtheist
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To: Vicomte13
If a computer can "prove" that only four colors are needed, then the computer is clearly in error.Computer is OK as long as all countires are contiguous. Since they aren't you are right, the computer is in error when talking about maps of the world.
To: ILikeFriedman
Here's a slightly less complex version of it:
Given a=b, prove that 1=2.
PROOF:
a = b Given
a*b = b^2 Multiply both sides by b
a*b - a^2 = b^2 - a^2 Subtract a^2 from both sides
a(b-a) = (b+a)(b-a) Factor
a = b+a Divide both sides by (b-a)
a = 2*a Since a=b as originally given
1 = 2 Divide both sides by a
142
posted on
11/08/2005 6:49:04 PM PST
by
CardCarryingMember.VastRightWC
(The heart of the wise man inclines to the right, but the heart of the fool to the left. - Eccl. 10:2)
To: Freedom_Fighter_2001
I believe Whitehead and Russell already addressed that question. I only got thru the first half of Volume 2, so I don't know how it turned out.
My favorite, though, is to define "regular" to mean words that describe themselves, "irregular" to mean words that do not describe themselves.
BTW, the barber was a Cretin.
143
posted on
11/08/2005 8:32:09 PM PST
by
boojumsnark
(Time flies like an arrow; fruit flies like a banana.)
To: CardCarryingMember.VastRightWC; ILikeFriedman
Of course you know your assumption is faulty. a cannot equal b in an ordered set of numbers.
144
posted on
11/08/2005 11:14:38 PM PST
by
phantomworker
(All roads lead back to Rome. Boldness has genius, power &magic in it..Begin your dissertation now!!)
To: null and void; Darksheare
Hey, what are you doing on this mathematician thread?
It must be Dark's fault!
145
posted on
11/08/2005 11:20:37 PM PST
by
phantomworker
(All roads lead back to Rome. Boldness has genius, power &magic in it..Begin your dissertation now!!)
To: Professional Engineer
146
posted on
11/08/2005 11:23:50 PM PST
by
phantomworker
(All roads lead back to Rome. Boldness has genius, power &magic in it..Begin your dissertation now!!)
To: MarkL
Isn't '42' the answer to the Ultimate Question of Life, the Universe, and Everything?
147
posted on
11/08/2005 11:29:30 PM PST
by
phantomworker
(All roads lead back to Rome. Boldness has genius, power &magic in it..Begin your dissertation now!!)
To: phantomworker
Isn't '42' the answer to the Ultimate Question of Life, the Universe, and Everything?Yup, but the problem is that nobody can remember exactly what the question was...
Mark
148
posted on
11/09/2005 5:21:20 AM PST
by
MarkL
(I didn't get to where I am today by worrying about what I'd feel like tomorrow!)
To: RightWingAtheist
I can trisect an angle with nothing but a compass and a straight-edge, but apparently it is impossible.
149
posted on
11/09/2005 5:23:48 AM PST
by
Flightdeck
(Longhorns+January=Rose Bowl Repeat)
To: MineralMan
When someone says prove "2 + 2 = 4", unless explicitly stated otherwise they mean base 10.
To: RightWingAtheist
Godel proved this over 70 years ago. In the pages of one slim paper he destroyed the arrogant contentions and made a mockery of the conceit of one of the most celebrated atheists of the age, Bertrand Russell, who, with Alfred North Whitehead, had set out to establish the secure and exact foundations of mathematics.
Incidently, Godel believed in the existence of God.
To: Vicomte13
Several people have pointed out why four is sufficient for Russia. My only comment on the "four colors" solution is that is limited to the practical example of existing maps. If by being "adjacent" requires only a single point of intersection on the border, than I can create abstract examples of any size N to show that N colors are insufficient:
Starting with N = 4... Picture a "four corners" scenario like the states in the US Southwest. No problem... even though they all intersect at a single point, you have four colors. However, if you add one region/state/whatever that surrounds all four (or also intersects at the same point), the you would need a fifth color. Repeat as necessary for every N + 1.
The problem is only solvable for N = 4 if "adjacent" requires more than one point of border intersection.
152
posted on
11/09/2005 5:41:27 AM PST
by
kevkrom
(Thank you... I'll be here all week. Don't forget to tip your waitress. (And try the veal!))
To: MineralMan
Comment #154 Removed by Moderator
Comment #155 Removed by Moderator
Comment #156 Removed by Moderator
To: DustyMoment
Greeks, Mayans and Aztecs
err... Aztecs??? I don't think they were so hot on maths, were they? (I may be wrong)
157
posted on
11/09/2005 6:15:23 AM PST
by
Cronos
(Never forget 9/11. Restore Hagia Sophia!)
To: ILikeFriedman
Your point
(a+b)=(a-b)/(a-b)=1
Then means (by resubstituting a=b=1)
1+1=(1-1)/(1-1)=1
2 = 0/0 = 1
You can't divide by 0.
158
posted on
11/09/2005 6:23:39 AM PST
by
Cronos
(Never forget 9/11. Restore Hagia Sophia!)
To: ShadowAce
yes- a map of one state needs only one color, two if you include bordering states (that do not also touch each other)
159
posted on
11/09/2005 6:33:31 AM PST
by
Mr. K
(Some days even my lucky rocketship underpants don't help...)
Comment #160 Removed by Moderator
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