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January 4, 2014 Planetary Alignment Decreases Gravity
www.newshound.net ^ | Dec 16, 2013 | news hound

Posted on 12/28/2013 5:00:34 PM PST by kjam22

It has been revealed by the British astronomer Patrick Moore that, on the morning of January 4th 2014, an extraordinary astronomical event will occur. At exactly 9:47 am, the planet Pluto will pass directly behind Jupiter, in relation to the Earth. This rare alignment will mean that the combined gravitational force of the two planets would exert a stronger tidal pull, temporarily counteracting the Earth’s own gravity and making people weigh less. Moore calls this the Jovian-Plutonian Gravitational Effect.

Astronomers have long been aware that there would be an alignment of the planets on that date, when Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune and Pluto would be on the same side of the Sun, within an arc 95 degrees wide. But now the effect could be expected as the gravitational effect of the other planets on the Earth’s crust is maximum even at their closest approach.

If you think you will be able to float around your house then you will be mistaken. BUT if you jump in the air at 9:47AM local time on January 4th 2014, it should take you about 3 seconds to land back on your feet instead of the usual 0.2 seconds.

(Excerpt) Read more at news-hound.net ...


TOPICS: News/Current Events
KEYWORDS: gravity; jupitereffect; planets; science
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To: kjam22

The earth pulls on you about 2.8 million times more than Jupiter does when it is closest to Earth. When it is farthest from earth, Earth’s pull is about 10 million times more than Jupiter’s.


51 posted on 12/28/2013 5:38:03 PM PST by Right Wing Assault
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To: kjam22
BUT if you jump in the air at 9:47AM local time on January 4th 2014, it should take you about 3 seconds to land back on your feet instead of the usual 0.2 seconds.

I'm calling it BULLCRAP.

52 posted on 12/28/2013 5:40:00 PM PST by Blood of Tyrants (From time to time the.tree of liberty must be watered with the blood of tyrants and patriots.)
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To: Secret Agent Man; saganite; armydoc
.3 seconds, not 3 seconds.

Not even close; even if Jupiter's mass suddenly doubled, he's missing 7 zeroes after the decimal point. The gory details are at Post #49

53 posted on 12/28/2013 5:40:50 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: Blood of Tyrants

Rats... I was really hoping to slam dunk on that day. Was gonna get my wife to video it and everything!


54 posted on 12/28/2013 5:41:34 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: FredZarguna

it did seem funny it would increase it by 50%.


55 posted on 12/28/2013 5:41:44 PM PST by Secret Agent Man (Gone Galt; Not averse to Going Bronson.)
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To: kjam22

Gee. I wonder which weight loss product will use this day to charge more for their product!?


56 posted on 12/28/2013 5:45:04 PM PST by Red_Devil 232 (VietVet - USMC All Ready On The Right? All Ready On The Left? All Ready On The Firing Line!)
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To: Red_Devil 232

I was thinking the lack of gravity might even help the obammycare website work faster... pretty sure it will!


57 posted on 12/28/2013 5:46:30 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: ReaganÜberAlles
This is baloney.

Utter baloney! I wonder if it's not meant as a joke.

Interesting fact: The tidal force of objects of the same density is proportional to their apparent area in the sky, measured by steradians, or square degrees if you like.

Note the sun and moon have the same apparent size, but the density of the sun is less than that of the moon, and it has a proportionately smaller tidal effect on the earth.

Likewise, Pluto's tidal effect may be estimated by its apparent angular area. It has an angular diameter of about 2000km/6 billion KM, so it's angular diameter is about 1/3billion, compared to the moon's 1/100. So the tidal effect of Pluto on the earth is about 1/30 million squared, or about 10-15 times the lunar tidal effect.

58 posted on 12/28/2013 5:48:12 PM PST by dr_lew
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To: Secret Agent Man
.3 seconds, not 3 seconds.

No, that is not it, either. If your jump lasts 0.2 seconds (which is pretty small for what most people can do) it is essentially 0.2 seconds no matter where the planets are. Their pull on us is miniscule compared to Earth's.

The article is seriously wrong.

59 posted on 12/28/2013 5:50:09 PM PST by Right Wing Assault
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To: kjam22
If you think you will be able to float around your house then you will be mistaken. BUT if you jump in the air at 9:47AM local time on January 4th 2014, it should take you about 3 seconds to land back on your feet instead of the usual 0.2 seconds.


60 posted on 12/28/2013 5:51:58 PM PST by Tolerance Sucks Rocks (...)
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To: kjam22
Pluto is about 12 times as far as Jupiter at closest approach, so since the distance is squared the force goes down by 144. Pluto is also 0.0022 the mass of the Earth, which is about 0.0000068 of the mass of Jupiter. This means that if the Earth exerts 29 million times as much force on you as Jupiter, then the Earth exerts a force which is 144/0.0000068 = 2.1 x 107 greater yet than Pluto does.

In other words, the effect of Pluto on gravity at the earth's surface is 1/(2.1 x 2.9 x 107 x 107) = 1/6 * 10-15. That's less than one part in a quadrillion. I doubt even the most sensitive torsion interferometers could even measure that effect.

61 posted on 12/28/2013 5:52:14 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: ErnBatavia

LMAO!


62 posted on 12/28/2013 5:53:35 PM PST by entropy12 (Great republics wither when more people figure out they can get free stuff by electing socialists.)
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To: kjam22

I like how they put this. If you jump you will have .3 seconds hangtime not .2 seconds. Why not say if you step on a scale you will weigh 150 lbs instead of 200 lbs. Cause that would be too easily disprovable.


63 posted on 12/28/2013 5:53:47 PM PST by Lurkina.n.Learnin (This is not just stupid, we're talking Democrat stupid here.)
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To: kjam22
Here's a computer graphic of the upcoming alignment.
64 posted on 12/28/2013 5:53:53 PM PST by Redcitizen (Never bring a tank to a Chuck Norris fight.)
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To: Right Wing Assault

When I was in highschool.... I could jump and just barely touch the rim on a 10 foot basketball goal. I’m 6 foot tall with a 32 inch sleeve. Now when I jump I can only touch about 3 or 4 inches of the bottom of the net. I was really hoping this day was going to turn back that aging process.... :)


65 posted on 12/28/2013 5:53:55 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: ReaganÜberAlles

Gravity is proportional to Distance squared. If those two planets are much closer to earth than sun at that particular moment, it could have more effect than just their mass ratios.


66 posted on 12/28/2013 5:55:53 PM PST by entropy12 (Great republics wither when more people figure out they can get free stuff by electing socialists.)
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To: Redcitizen

I’ve seen that on the big bang theory I think... :)


67 posted on 12/28/2013 5:56:07 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: kjam22
Three seconds does sound like a long time to “hang” in the air.....

Since the world record is 0.5 seconds, I believe you are correct.

68 posted on 12/28/2013 5:56:45 PM PST by Mrs.Z
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To: saganite

A decimal and some 0s.


69 posted on 12/28/2013 5:58:04 PM PST by arthurus (Read Hazlitt's Economics In One Lesson ONLINEhttp://steshaw.org/economics-in-one-lesson/)
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To: Right Wing Assault
The earth pulls on you about 2.8 million times more than Jupiter does when it is closest to Earth.

Oops! That should be about 28 million.

70 posted on 12/28/2013 5:59:22 PM PST by Right Wing Assault
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To: 75thOVI; agrace; aimhigh; Alice in Wonderland; AndrewC; aragorn; aristotleman; Avoiding_Sulla; ...
if you jump in the air at 9:47AM local time on January 4th 2014, it should take you about 3 seconds to land back on your feet instead of the usual 0.2 seconds.
Ludicrous, or maybe quaaludicrous. Jupiter Effect flashback. Thanks kjam22.

71 posted on 12/28/2013 6:02:00 PM PST by SunkenCiv (http://www.freerepublic.com/~mestamachine/)
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To: kjam22
physics photo:  physics-1.jpg
72 posted on 12/28/2013 6:02:05 PM PST by Snickering Hound
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To: kjam22
What happens if everyone on earth jumps into the air at 9:47 a.m. local time on January 4, 2014? Zombie apocalypse?

And what's all this about planet Pluto? (I thought there wasn't a planet Pluto.)

73 posted on 12/28/2013 6:02:43 PM PST by Pajamajan (Pray for our nation. Thank the Lord for everything you have. Don't wait. Do it today.)
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To: entropy12
it could have more effect than just their mass ratios

Yes, but it's still essentially immeasurable.

74 posted on 12/28/2013 6:03:28 PM PST by Right Wing Assault
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To: Pajamajan
2 things. If everyone on earth jumps in the air at the same time.... the earth turns a semi-turn faster at that moment. And two... the obammycare website works faster if everyone on earth is doing something else than hitting it.
75 posted on 12/28/2013 6:05:31 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: kjam22

I’m 5’9” and at my best I needed a 1.5 foot head start!


76 posted on 12/28/2013 6:06:10 PM PST by Right Wing Assault
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To: dr_lew

Doh!

I mis-recalled my back-of the envelope calculation, which uses MG/R^2 X d/R as the force, where d is the distance on the earth from the earth’s center. Of course, there’s a tensor involved to give you the direction of the force, but we’re just concerned with the magnitude here.

Then we just use M = rho r^3, where rho and r are the density and diameter of the moon or planet exerting the tidal force, and we see we have rho G (r/R)^3 X d. So it’s the CUBE of the angular size, not the square. So make that 10^-23 instead of 10^-15.

... but the point remains the same.


77 posted on 12/28/2013 6:10:47 PM PST by dr_lew
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To: FredZarguna

Of course the tidal effect is the differential effect of another object’s gravitational pull on the earth and objects nearby. The earth and everything on it is in free fall in the object’s force field, and it is the difference between the force on points slightly displaced from each other that constitutes the tidal force field.


78 posted on 12/28/2013 6:15:27 PM PST by dr_lew
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To: kjam22

Patrick Moore is dead.


79 posted on 12/28/2013 6:17:03 PM PST by ElkGroveDan (My tagline is in the shop.)
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To: SunkenCiv

It only works if you believe.............


80 posted on 12/28/2013 6:18:51 PM PST by Eaker (Sweat dries, blood clots and bones heal so suck it up buttercup.)
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To: kjam22

Find something solid and hang on tight to it!


81 posted on 12/28/2013 6:22:14 PM PST by TigersEye (Stupid is a Progressive disease.)
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To: ElkGroveDan

Still??? I thought he was Roger Moore’s brother. Double 0 8.


82 posted on 12/28/2013 6:24:51 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: kjam22

Jupiter is in Gemini, Pluto is on the opposite side of the sun in Sagittarius.

There is no such alignment


83 posted on 12/28/2013 6:28:56 PM PST by qam1 (There's been a huge party. All plates and the bottles are empty, all that's left is the bill to pay)
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To: qam1

I guess we had a lunar eclipse last night/ early this morning? I didn’t get up to see it...


84 posted on 12/28/2013 6:38:54 PM PST by kjam22 (my newest music video:http://www.youtube.com/watch?v=l7gNI9bWO3s)
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To: kjam22

. If everyone on earth jumps in the air at the same time.... the earth turns a semi-turn faster at that moment.


Doubt it.


85 posted on 12/28/2013 6:49:20 PM PST by loungitude (The truth hurts.)
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To: dr_lew
You are replying to a post which is actually continued from post #49. In post 49 I show that the gravitational force exerted by the Earth is roughly 29 million times greater than the force exerted by Jupiter. In that post I mention that you could double Jupiter and see a gravitational effect on the order of 1/10,000,000, that effect would be many times greater than the additional alignment of Pluto.

Someone naturally speculated what the actual effect of even more distant Pluto would be. The answer is that it is about 20 million times weaker still.

The speculation in this article -- while wildly wrong -- does not involve tidal forces.

The tidal force is not a differential adjustment in the gravitational effect on nearby points, which is almost always negligible. [It goes as -2dr/r. For the moon, the effect on points separated by 1m is 2 parts in 300,000,000. This is not even detectable. So slightly displaced doesn't cut it.]

The tidal effect arises because for bodies of large spatial extent, there are measurable differences between the gravitational attraction on opposite (or even widely separated) parts of the object. For the moon, the maximum effect is around 6/300. At 2% it is not negligible, but the most dramatic effect is observed at 12,000 Km apart. That's not slight displacement, even when considering LD as a unit of measure.

86 posted on 12/28/2013 6:56:56 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: loungitude; kjam22
Mass of Earth 6 x 10 24 Kg. Mass of 6 billion humans, even if all were average American-sized adult males 6 x 10 9 x 100 kg. that's 1 part in 1013, i.e. one part in ten trillion. Wouldn't even be measurable.
87 posted on 12/28/2013 7:00:54 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: Eaker

Heh... and there will be people who will swear it happened.


88 posted on 12/28/2013 7:00:54 PM PST by SunkenCiv (http://www.freerepublic.com/~mestamachine/)
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To: entropy12; ReaganÜberAlles

The closest Jupiter ever gets to us is 6 times further than the sun. The closest pluto ever gets is about 70 times further than the sun.


89 posted on 12/28/2013 7:03:43 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: MaxMax

We have no idea what causes Gravity
********************
This has been a fun thread to read. Your comment reminded me of something.

In 1968, my employer sent me to the university in Iowa City IA for a two week seminar on statistics. At the entrance to the student union bldg. there was a very large chalk board where students were allowed to write pithy statements.

One such comment was, “There is no such thing as gravity! The Earth sucks!”


90 posted on 12/28/2013 7:06:14 PM PST by octex
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To: FredZarguna

The immeasurable part is acceptable.
The theory part is that no rotational kinetic energy is lost in the ‘everybody jumps up at the same time’ scenario.


91 posted on 12/28/2013 7:10:44 PM PST by loungitude (The truth hurts.)
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To: SunkenCiv
The dumbest thing about the whole article that nobody bothers to point out is that these planets are moving continuously toward this alignment. The gravitational effect theorized does not suddenly "turn on" like a light switch and then suddenly "turn off" when the alignment "ends."

If any measurable floating effect were going to happen at alignment, we would see a very significant amount of it happening already, slowly building toward this fabulous 3 second float, which would slowly trail off as the planets move out of alignment.

92 posted on 12/28/2013 7:12:12 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: kjam22; SunkenCiv

Oh dear, what are we going to do about it?


93 posted on 12/28/2013 7:25:19 PM PST by Berosus (I wish I had as much faith in God as liberals have in government.)
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To: loungitude
Conservation of rotational kinetic energy -- which I agree doesn't change -- requires the angular velocity of the Earth to decrease when the jumpers jump.

The moment of inertia of the system composed of the Earth and jumping people will change. In order to conserve angular momentum -- which must be conserved because there is no external torque -- the angular velocity, ω, must decrease. [In your alternative formulation, there are no external sources of energy, therefore the angular velocity must decrease when I increases in order for the kinetic energy to remain constant: Iiωi2 = Ifωf2]

The differential dI would (at most, assuming the people ball themselves up into spheres when they jump) would be 2m * r * dr, where r is the radius of the earth, dr is the number of meters they jump, and m is the mass of six billion people. The number is insignificant compared to the moment of inertia of the Earth, which is roughly 2/5 M r2, where M is the mass of the Earth. And it is clearly this which dominates.

94 posted on 12/28/2013 7:30:11 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: Secret Agent Man
The other thing, which I point out elsewhere, is that these planets are moving continuously towards this alignment. The gravitational forces for one planet can always be resolved into a vector that points along the same axis as the other planet, plus an additional vector which is tangent to that. The tangent vector gets smaller and smaller as the planets approach alignment, and at full alignment the radial component straight along one single direction towards the earth is at its maximum additivity.

What does this mean?

It means the effect, however large it is would already be seen. It doesn't just magically "turn on" like a light switch when the planets align and then instantly "turn off" when the planets are no longer aligned. It would build continuously toward a maximum, just like the length of the day does, and then fall off slowly once the planets are no longer aligned.

Whatever "magic float effect" there might be would already be well underway -- if it existed.

But it doesn't.

95 posted on 12/28/2013 7:41:29 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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To: FredZarguna
The tidal force is not a differential adjustment in the gravitational effect on nearby points, which is almost always negligible. [It goes as -2dr/r. For the moon, the effect on points separated by 1m is 2 parts in 300,000,000. This is not even detectable. So slightly displaced doesn't cut it.]

The "-2" in -2dr/r is the -2 in the tidal tensor and represents the stretching effect along the axis of attraction, as represented by the first order term of the power series expansion.

The displacement is considered "slight" in the sense that the first order term is much larger than higher order terms.

Also, whether one uses higher order terms or not, the whole treatment is of a differential force.

The speculation in this article -- while wildly wrong -- does not involve tidal forces.

It says, " This rare alignment will mean that the combined gravitational force of the two planets would exert a stronger tidal pull, ..." Sheesh!

96 posted on 12/28/2013 8:04:11 PM PST by dr_lew
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To: qam1; All

It only too 80+ post for someone to point out that the problem isn’t the gravity, but that they are in opposite parts of the sky on Jan 4th.

Got to be a record.


97 posted on 12/28/2013 8:10:05 PM PST by Conan the Librarian (The Best in Life is to crush my enemies, see them driven before me, and the Dewey Decimal System)
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To: kjam22; Revolting cat!; Slings and Arrows

Weight loss in 2014!

Diet is ovah.


98 posted on 12/28/2013 8:27:50 PM PST by a fool in paradise ("Health care is too important to be left to the government.")
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To: 21twelve

I think even a tenth of a second is total BS. More like .00000000001 seconds.


99 posted on 12/28/2013 8:29:06 PM PST by SampleMan (Feral Humans are the refuse of socialism.)
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To: dr_lew
Oh good grief. In an article that clearly has no clue whatsoever, we are to take the pronouncements of some idiot journo at face value.

There are no tidal forces involved in the phenomenon described.

The article clearly says if you jump you will take longer to come down; that isn't a tidal effect. A tidal effect would be that the wrinkles on your face form more slowly than the wrinkles on your toes, or that water splashed into the air will form slightly more elongated bubbles during this alignment. [AND ... Neither of these things happens because even with planetary sized bodies tidal effects are, within experimental error, entirely first order effects.]

The -2 in the -2dr/r is not a tensor. The expression is just the differential: d(2Gm1m2/r2) Unless you're claiming that scalars are tensors. OK, they are. But no actual physicist calls a scalar a tensor. As a matter of fact the first order term in the expansion is a vector, and it points radially, and again, nobody but the prissiest mathematician on the planet actually calls a vector a first order tensor.

In any event, you are simply wrong. This article talks about a "tidal" effect to give it an air of authority, but the effect described is not the least bit tidal. It's simply a gravitational effect, and about 15 orders of magnitude smaller than claimed.

100 posted on 12/28/2013 8:36:00 PM PST by FredZarguna (Nobody so soundly whipped is entitled to a rematch.)
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