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To: honway
"The process uses 15 Btus to produce 100 Btus."

With math like that I am not surprised this approach appeals to you. My original statement is correct: 100 BTUs in (feedstock); 85 BTUs out (useful energy).

Period.

--Boris

74 posted on 04/21/2003 11:08:30 AM PDT by boris (Education is always painful; pain is always educational)
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To: boris
With math like that I am not surprised this approach appeals to you. My original statement is correct: 100 BTUs in (feedstock); 85 BTUs out (useful energy).

The point is that it is 100 BTUs of waste material (not useful energy) being run through a process to turn it into 85 BTUs of fuel (useful energy). Given that the waste material is waste, that's like putting rocks into a blender and getting oil for the energy needed to run the blender. 15% is incredibly efficient. FYI, normal chemical-to-electrical power plants lose about half the energy during the conversion.

86 posted on 04/21/2003 12:16:17 PM PDT by Question_Assumptions
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To: boris
My original statement is correct: 100 BTUs in (feedstock); 85 BTUs out (useful energy).

That feedstock is otherwise useless crap that would actually take resources to dispose of. You arent putting 100 btus of USEFUL energy in.

114 posted on 04/22/2003 9:04:16 AM PDT by Britton J Wingfield
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