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To: Diamond
The metabolic energy cost of manufacturing them. If most of your DNA is "filler" what is the selective advantage of excessive spreading of functionless replicators? Y

Conservatively, I estimate you probably have to use two molecules of glucose to provide the energy and materials to make one nucleotide and insert it into DNA. The L-GLO pseudogene has about 1000 base pairs, or 2000 nucleotides. If there's one copy in every one of the 5 X 1013 cells of the body, to produce two L-GLO pseudogenes in every cell of the body, you need 2 X 2 X 2000 X 5 X 1013 = 4 X 1017molecules of glucose, or about 7 X 10 -7 moles. The molecular mass of glucose is 180 g/mol, so this corresponds to approximately 125 micrograms of glucose. So a human possessing the L-GLO pseudogene needs to eat 125 micrograms more glucose to synthesize all the L-GLO pseudogenes every cell in the body will ever have. Turnover times for human DNA vary from days to decades, depending on which cells we're discussing; but if we take a mean of 100 days, you require 1.25 micrograms of extra glucose a day to maintain the L-GLO pseudogene.

And that assumes degraded DNA is not recycled, which of course it is.

528 posted on 04/20/2006 8:44:23 AM PDT by Right Wing Professor
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To: Right Wing Professor
Of course your calculation is correct regarding this one superfluous short DNA sequence, but the L-GLO pseudogene energy component is just a tiny fraction of all the alleged "filler" DNA. So when the total amount of superfluous short DNA sequences become comparable to or greater than that of useful DNA, why wouldn't the selective disadvantage be significant?

Conversely, if there is no selective pressure on this not too harmful DNA, which by the way we're told constitutes most of your DNA, then why wouldn't ‘old’ pseudogenes be scrambled beyond recognition as a result of accumulated random mutations?

Cordially,

534 posted on 04/20/2006 9:11:17 AM PDT by Diamond
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To: Right Wing Professor
The L-GLO pseudogene has about 1000 base pairs, or 2000 nucleotides. If there's one copy in every one of the 5 X 1013 cells of the body, to produce two L-GLO pseudogenes in every cell of the body, you need 2 X 2 X 2000 X 5 X 1013 = 4 X 1017molecules of glucose, or about 7 X 10 -7 moles. The molecular mass of glucose is 180 g/mol, so this corresponds to approximately 125 micrograms of glucose. So a human possessing the L-GLO pseudogene needs to eat 125 micrograms more glucose to synthesize all the L-GLO pseudogenes every cell in the body will ever have.

Nicely done! Oh, well played, sir!

Watch your significant figures! :-P

Cheers!

594 posted on 04/20/2006 7:34:13 PM PDT by grey_whiskers (The opinions are solely those of the author and are subject to change without notice.)
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To: Right Wing Professor
"Conservatively, I estimate you probably have to use two molecules of glucose to provide the energy and materials to make one nucleotide and insert it into DNA. The L-GLO pseudogene has about 1000 base pairs, or 2000 nucleotides. If there's one copy in every one of the 5 X 1013 cells of the body, to produce two L-GLO pseudogenes in every cell of the body, you need 2 X 2 X 2000 X 5 X 1013 = 4 X 1017 molecules of glucose, or about 7 X 10 -7 moles. The molecular mass of glucose is 180 g/mol, so this corresponds to approximately 125 micrograms of glucose. So a human possessing the L-GLO pseudogene needs to eat 125 micrograms more glucose to synthesize all the L-GLO pseudogenes every cell in the body will ever have. Turnover times for human DNA vary from days to decades, depending on which cells we're discussing; but if we take a mean of 100 days, you require 1.25 micrograms of extra glucose a day to maintain the L-GLO pseudogene.

"And that assumes degraded DNA is not recycled, which of course it is.

Darn! You took the words right out of my mouth. ;)

601 posted on 04/20/2006 7:56:49 PM PDT by b_sharp (A lack of tag line is not a)
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