The key equation is the following; When the time $\nu $ is sufficiently large, the volume is given by:
\[ V \approx 3\sqrt{3}\pi M^2 \nu . \]
Untangling this mashup of ill-conversion leaves us with the following;
When the time ν is sufficiently large, the volume is given by;
V≅ 3√3 π M^2 ν
Remember the 'distributive property'
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