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School math question. Your input?
Posted on 03/10/2015 5:48:37 PM PDT by MNDude
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To: MNDude
61
posted on
03/10/2015 6:29:40 PM PDT
by
ThomasThomas
(EGO venit lego tantum titulus Posteri)
To: MNDude
According to Common Core, first you have to make friends with the ten in the twelve. Then you have to add another friend to make twenty. From the twenty, you have to add the one and the two from the twelve to make twenty-three. Now, two plus three is five, which you add to the original twelve to get seventeen. But since you added three numbers together, you take back three from seventeen to get fourteen, and there’s your answer: B.
62
posted on
03/10/2015 6:29:41 PM PDT
by
Talisker
(One who commands, must obey.)
To: MNDude
14 units
It is 12 square units, therefore, 3units up top, 3 units on the bottom, 4 units to the left, and 4 units to the right.
Does the diagram below help?
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[ ]
] ]
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To: kalt
To: MNDude
If it was shaped like this the perimeter would be 18.
65
posted on
03/10/2015 6:32:11 PM PDT
by
Clint N. Suhks
(Bibi is the President we wish we had.)
To: MNDude
Assuming whole units and a rectangular shape it must be an even number, and therefore B is the only available choice.
What grade is this for?
66
posted on
03/10/2015 6:33:14 PM PDT
by
BlueNgold
(Have we crossed the line from Govt. in righteous fear of the People - to a People in fear of Govt??)
To: MNDude
Insufficient information. This is just the kind of problem that a teacher with no grounding in math will give to a student, then look in the key to answer.
To: Talisker
68
posted on
03/10/2015 6:34:08 PM PDT
by
jjotto
("Ya could look it up!")
To: Thurifer the Censer
3 x 4 would be 14, 2 x 6 would be 16, and 1 x 12 would be 26.
There are an infinite number of answers. It's a system of 2 equations in 3 unknowns. The answer that minimizes is 13.86 (approximately), which occurs for a square.
69
posted on
03/10/2015 6:35:13 PM PDT
by
FredZarguna
(O, Reason not the need.)
To: Attention Surplus Disorder
First thing I did was assume a rectangle and digest the square roots to define the lower limit. C and D could be acieved, but not using whole units.
70
posted on
03/10/2015 6:35:37 PM PDT
by
BlueNgold
(Have we crossed the line from Govt. in righteous fear of the People - to a People in fear of Govt??)
To: MNDude
We do not know the width of the border. Only its length. therefore, one cannot determine how many units are needed at the corners to meet the border corners. Suppose the border is 2X Units in width and the blanket 3x4 units. The border would have to be 3 units on two sides and 8 units on two sides to have the corners meet.
71
posted on
03/10/2015 6:35:39 PM PDT
by
anton
To: MNDude
Answer is 14 units.
Area is 12 Square
4+4+3+3
or
6+6+2+2 = 16 Since that’s not one of the choices. you’re left with 14.
72
posted on
03/10/2015 6:37:36 PM PDT
by
Ouderkirk
(To the left, everything must evidence that this or that strand of leftist theory is true)
To: Half Vast Conspiracy
I’m a reading specialist. One year they assigned me as a co-teacher in a 6th grade math class. It didn’t last because I kept analyzing the story problems and coming up with the wrong answers....I swear this is true!
To: Jonty30
...10 units needing covering
What?
To: MNDude
W=WIDTH, L=LENGTH
L*W = 12
and
2(L + W) = x (where x is one of the four possible values)
solve first eq for W...
W = 12/L
substitute in second giving
2L + 24/L = x
divide by 2...
L + 12/L = x/2
multiply both sides by L and rearrange...
L^2 - (x/2)L + 12 = 0
substituting each value (12,14,15,21) into this eq yields a quadratic that can be solved.
Answer “A” has no real roots, but B,C, and D all have nondegenerate real roots, therefore B,C or D are valid answers, but not A.
75
posted on
03/10/2015 6:38:35 PM PDT
by
SpaceBar
To: RetiredTexasVet
15 works too.
L= 5.186
W+ 2.314
76
posted on
03/10/2015 6:38:50 PM PDT
by
lkco
To: eastforker
Not true. 15 works also (L= 5.186, W=2.314)
77
posted on
03/10/2015 6:39:43 PM PDT
by
lkco
To: Attention Surplus Disorder
However, The State wants you to answer 14 feet.
We've got a winner!
To: Clint N. Suhks
πab is the area if it's an ellipse, but the perimeter is an elliptic integral, not solvable in closed form. The power series is
79
posted on
03/10/2015 6:40:58 PM PDT
by
FredZarguna
(O, Reason not the need.)
To: SpaceBar
nondegenerate positive real roots
80
posted on
03/10/2015 6:41:06 PM PDT
by
SpaceBar
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