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To: avg_freeper

If this is a centripetal weapon, doesn’t this mean theoretically the opposing force of the exit volicty would be distributed along the entire centripetal loop (or path), thus giving a great force with little true recoil as it is spread evenly around the circle?


42 posted on 05/11/2005 1:29:27 PM PDT by mnehring (http://www.mlearningworld.com)
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To: mnehrling

There is no opposing force. The mechanism that spins the bearings gives them energy; when the bearings are 'fired', they are mearly released.


56 posted on 05/11/2005 1:36:19 PM PDT by Sofa King (MY rights are not subject to YOUR approval.)
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To: mnehrling; Lazamataz; Travis McGee

Your car tire is a centrifugal weapon when it throws a rock out of its tread into your fender. Similar recoil, or lack thereof, for the weapon in this article, too. It's actually negative recoil, as mass is leaving because it is released instead of pushed...you'd be hard-pressed to feel such minute negative recoil, though.

70 posted on 05/11/2005 1:44:19 PM PDT by Southack (Media Bias means that Castro won't be punished for Cuban war crimes against Black Angolans in Africa)
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