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To: FreepShop1

58.6 feet per second at 40MPH

A little over 10 seconds assuming no increase in speed during the fall...


15 posted on 07/14/2009 9:45:31 AM PDT by bill1952 (Choice is an illusion created between those with power - and those without)
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To: bill1952
. . . assuming no increase in speed during the fall . . .

Bet he had his foot on the break pedal.

27 posted on 07/14/2009 9:53:01 AM PDT by Fester Chugabrew
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To: bill1952

If you assume “assuming no increase in speed during the fall...” then he’d still be floating in the air at 600 ft.


102 posted on 07/14/2009 10:57:24 AM PDT by pelican001
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To: bill1952
>>>assuming no increase in speed during the fall...<<<

Repealing the Law of Gravity? Even Obama hasn't attempted that!!

103 posted on 07/14/2009 10:58:59 AM PDT by HardStarboard ("The urge to save humanity is almost always a false front for the urge to rule - Mencken knew Obama)
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To: bill1952; MikeWUSAF
Unless the car was launched at an angle, the horizontal speed of the car is not relevant to the vertical distance it fell.

The formula to use is d = 0.5 * g * t^2.
Solving for t would give sqrt(600 ft * 2 / 32 ft/sec^2)= 6.1 seconds.

In those 6.1 seconds the car would travel (6 sec) * (40 mi/hr) * (5280 ft/mi) / (3600 sec/hr) = 358 ft away from the canyon wall, assuming the canyon wall was vertical and the horizontal speed of the car remained constant.

124 posted on 07/14/2009 12:48:55 PM PDT by Cooter
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