[r9etb]

How’d I do?

Terrible. The 40 mph governs how far out in the canyon he will travel over the time taken to fall 600 feet.

The time required to drop 600 ft. is driven by gravity, coupled with the initial downward speed of the car.

From your freshman physics class, you will recall that

d = d₀ + v₀t + 1/2 a_grav t²

Since he drove off the edge horizontally, his initial downward speed v₀ is approximately zero, as is his initial distance, d₀.

Thus,

d = 1/2 a_grav t²

d = 600 ft, and a_grav = 32.174 ft/sec^2.

So we can solve for t to get a "hang time" of about 6.1 seconds.

Over that time he would travel approximately 360 feet out from the edge of the canyon.

[advertising guy]

lmao

[TSgt]

From your freshman physics class, you will recall that

Yeah, I didn't do so well in that...

But you know, until this question I've never had the need to use anything from that class!