$7,000,000.00 is roughly 243 pounds @1800 per ounce. That would be a mighty BIG shoebox.
“$7,000,000.00 is roughly 243 pounds @1800 per ounce. That would be a mighty BIG shoebox.”
Not really. How big is a shoebox? 7” x 4” x 12”? (just making that up)
= 336 cu inches.
The density of gold is 19.3 grams per cubic centimeter. 1 inch = 2.54 cm, so 1 cubic inch = (2.54 cm)3 = 16.387 cm3. Multiply volume x density: (19.3 g*cm-3)*(16.387 cm3) =
316.27 grams in a cubic inch.
Times 336 = 112,986.7 grams in a shoebox. Divided by 453 grams per pound, and you’ll probably fall over when I tell you that a 4*7*12 shoebox holds 249.41 lbs of gold!
I’ll take the extra .6 lbs as my accounting fee, thank you very much!
I am calculating the above in avoirdupois pounds, gold and silver are weighed in troy ounces and (far less frequently, troy pounds) but you get the idea. Let’s just say it would have to be a VERY STRONG shoebox.
At 1200 pounds per cubic foot, that figures to 0.2 cubic feet or 345 cubic inches. A shoe box of 10" by 6" by 6" would be 360 cubic inches. That is a small pair of feet. A typical shoe box could handle this amount.
The bars at Fort Knox are about 27# each. So it would be the equivalent of about 9 bars. You could fit it all in a boot box - that you couldn’t lift.