Free Republic
Browse · Search
News/Activism
Topics · Post Article

To: Physicist
No this isn't from Roland Dishington. I just asked if you heard of him.

So is charge fixed to a moving dielectric considered a current? Is the electric field of this moving charge (that is, current) in the direction of the current density vector? Or is there no electric field of the charge in motion because it is mechanically forced to move?

I'm trying to do the Lorentz contraction calculation for the MM experiment. My problem is in determining the velocity of the apparatus. Is it just the tangential velocity at the earth's surface due to rotation or do I have to add the velocity of the earth going around the sun or also include the velocities of the solar system as well? What reference frame is used for the Lorentz contraction calculation? I'm confused because there is no relative motion between the observer and apparatus. Could you help me with this?

112 posted on 11/02/2002 7:39:17 AM PST by Barry Goldwater
[ Post Reply | Private Reply | To 104 | View Replies ]


To: Barry Goldwater
I'm trying to do the Lorentz contraction calculation for the MM experiment. My problem is in determining the velocity of the apparatus. Is it just the tangential velocity at the earth's surface due to rotation or do I have to add the velocity of the earth going around the sun or also include the velocities of the solar system as well? What reference frame is used for the Lorentz contraction calculation? I'm confused because there is no relative motion between the observer and apparatus. Could you help me with this?

If I recall correctly, the original MM idea was to determine if the motion of the earth, relative to the presumably stationary aether, made any difference in the transit time of the light beams. The motion of the entire solar system, and the galaxy, etc., would be common features to any such measurement, and could thus be ignored.

113 posted on 11/02/2002 7:54:00 AM PST by PatrickHenry
[ Post Reply | Private Reply | To 112 | View Replies ]

To: Barry Goldwater
So is charge fixed to a moving dielectric considered a current?

Yes.

Is the electric field of this moving charge (that is, current) in the direction of the current density vector?

No. In fact, Lorentz contraction causes the electric field from a moving charge to become weaker along the axis of motion and stronger in the transverse direction. The field becomes compressed along the axis of motion.

If you think carefully--very carefully--about this, it might seem that this gives rise to a situation that is not Lorentz invariant: as the charge passes by a "stationary" test charge, a stationary observer should expect the test charge to be subjected to a greater electostatic force than would be measured by an observer that is comoving with the moving charge. What's a test charge to do?

As it turns out, this difference in force is exactly compensated by the magnetic field that is observed by the stationary observer, created by the motion of the moving charge. This field is not observed by the comoving observer. They agree on the net motion of the test charge.

In other words, the magnetic field is the manifestation of effect of Lorentz contraction and time dilation upon an electric field. It's relativity you can play with at home.

Or is there no electric field of the charge in motion because it is mechanically forced to move?

The total electric field around the charge is invariant. Gauss's Law, once again. There is no additional electric field that is created by the movement of the charge. Battery, black hole, or baseball bat, it doesn't matter what causes the charge to move. The divergence of the field equals the charge density, end of story.

I'm confused because there is no relative motion between the observer and apparatus.

Then that's the frame you use for that observer. The issue is that a moving observer will also have to observe a null result for that apparatus. It has to work in all possible reference frames. The different observers aren't entitled to disagree about the outcome of the experiment; either the interference fringes shift or they don't. They will, however, disagree about the size of the interferometer.

114 posted on 11/02/2002 8:15:09 AM PST by Physicist
[ Post Reply | Private Reply | To 112 | View Replies ]

Free Republic
Browse · Search
News/Activism
Topics · Post Article


FreeRepublic, LLC, PO BOX 9771, FRESNO, CA 93794
FreeRepublic.com is powered by software copyright 2000-2008 John Robinson