Posted on 03/21/2007 10:31:06 AM PDT by rrr51
I was listening to the hearings and just heard AlGore say that natural CO2, such as CO2 produced by volcanos, is heavier than CO2 produced by man. Did I hear right? Is that what he said? Is it true? Does anybody know?
Now, Robert, don't confuse the discussion, by bringing up abiotic oil...LOL
Sorry, I don't know.
I am sooo relieved that you cleared that up for me....the divinity school flunkie had me scared.
For any particular element, there is more than one stable isotope, so the number of neutrons can vary. Stable just means that the decay is on the order of the age of the universe, near it. The assemblies of protons and neutrons themselves are lower, and higher energy configurations. The iron nucleus has the lowest energy configuration. Elements below iron fuse to approach iron, and those of higher atomic weight split.
For carbon, both 12C and 13C are stable. 14C is not, and has a half life of ~5700yrs. In chemical bonding, the weight of the nuclei are important. They effect the value of the reduced mass of the nuclear/electron system, and the nuclear/nuclear system. In a 2 body system, both masses move about the center of mass. In order to solve and simplify the problem, the 2 body problem is transformed into a problem consisting of one infinite mass at the center of mass, and another reduced mass, that is movable. For a one electron atom, the energy levels of the electron are directly proportional to the reduced mass, so as the nuclear mass increases, the magnitude of the energy level of the electron increases.
Since the electron is bound, the sign of the energy is negative. So, as the mass of the nucleus increases, the electron falls into a deeper well. It is bound tighter. The ionization energy for deuterium, 2H, or D, is ~0.1% higher than for regular hydrogen, 1H. So, the spectrum of D is shifted to shorter wavelengths s bit, and tritium, 3, even more so. That's because the reduced mass of the electron increases.
For bonding of 2 atoms, the nuclear motion, and the electronic motions can be separated. That's called the Born-Oppenheimer approximation. The above holds for the electronic motion, and the energy of the electrons involved in the binding is more negative, as the mass of the nuclei increases. The nuclear motions follow the same, as the mass increases, the 2 are effectively bound tighter. Their vibrational frequencies are lower, which means the well is deeper, and their ground states, or zero point energies are lower. That doesn't mean "the spring" binding them has a higher force constant. It just means "the spring" is harder to break.
The spring is still the electromagnetic force. What makes the spring harder to break, or a stronger bond, is that the mass of the nucleus moves less. In molecular binding the electrons involved in the bonding will be in more stabilizing trajectories than is possible if the nuclei move in a greater range of motion. The stability of the system is really the result of summing all the possible trajectories of the electrons involved, and minimizing the total energy. If the nuclear masses move to a smaller extent, their are less high energy possibilities. Also, when more than one electron is involved in the binding, the electrons "correlate" their motion to lower electron-electron repulsion. When the nuclear mass increases, there are less high energy correlations for the same nuclear charges. ...they're less probable.
So, D in D22. As the element's atomic number increases, the effect of nuclear mass decreases, because the percentage increase in mass decreases. So as 13C is 8% heavier than 12C, the binding energy is greater. That means compounds involving 12C will react easier than those involving 13C. So in any system involving these reactions, 12C will concentrate in the products, and more 13C will be left as reactant. As the elements mass increases, this fractionation effect becomes smaller. That's why uranium isotopes, are separated by physical means in a great number of steps.
Here's an example of fractionation of isotopes through another physical process for oxygen. In this case it's the increase in E needed to vaporize the higher mass isotope, that results in separation. Note gravity is irrelevant. It's the inertial mass that needs more E to move it out of a bound position that's important.
Of course it's true, just like everyone knows that a pound of lead is heavier than a pound of feathers ;-)
Sorry, that should have read:
So, D in D2 is ~1.3% lower in energy than H in H2. The D2 bond is ~1.3% harder to break, or a ~1.3% stronger bond.
I didn't take physics. Thanks for the explanation. I'll keep reading it and trying to understand it. :)
I left a mistake in there from typing fast. The ionization energy of a D atom is ~0.03% greater than an H atom, not ~0.3%.
The isotope that's important is the stable isotope 13C. 12C is preferentially incorporated into vegitation, because the 13C/oxygen bond is slightly stronger, than the 12C/O bond. That results in an increased isotopic ratio of 13C/12C in the atmosphere, over the general natural abundance ratio. See #284. There's some corrections in 2 posts below it, a missing H for 3H...
" UNLESS you consider petroleum based oils are NOT from "plant-life" derivatives, in which case they come from ?"
14C would be irrelevant in this case, because the oil is millions of years old, and the half life of 14C i ~5700yrs.
See #284, there's some corrections in posts below it. The vib freq drops as the reduced mass goes up. The well for the bound particles also gets deeper as the mass increases. The force constant stays the same, because it's the same electrostatics. The bond is just harder to break, because it takes more energy to move a higher mass.
The change in vibrational frequencies would have an effect on the rotational spectrum as a 2nd order effect through the coupling of vibration and rotation.
All the same, I appreciate your taking the time to answer courteously, even if it didn't turn out to be what I was so haughtily demanding ;-)
Cheers!
It's the vib-rottional spectrum that results in the energy absorbtion. They are coupled. Yes, water is the major greehouse gas, and CO2 only amounts to a small percentage. The isotope effect here is negligable. Isotopes are just used to measure flux of CO2 into and from various sources and sinks.
"The change in vibrational frequencies would have an effect on the rotational spectrum as a 2nd order effect through the coupling of vibration and rotation."
A vibrational transition must be accompanied by a rotational tranisition. It's a moment of inertia change. So, each vib band is broadened on both sides of a non-appearing center frequency. There's also transitional energy, which amounts to doppler broadening. The isotope effect is buried in there, so assuming it's all one isotope is good enough. Any 13C, or 14C effectively just increases the conc of 12C.
It will slightly lower the fundamental bands. But when you are talking about long path length gas phase spectroscopy, with very fine bands, such a shift will place absorbaces in regions C12 doesn't absorb. This is all around 500 cm-1 or so (black body at 20'C, or so).
Thanks, exactly what I was looking for.
Cheers!
small wonder. I stayed at a Holiday Inn last night so this was pretty trivial.
yes, much denser. see my post above for explanation.
denser at point of creation but also the effect intensifies with time. its just simple chemistry
Please explain the mechanism by which carbon dioxide, in any form, causes atmosphereic warming or retention of heat. I have yet to read a comprehensive description of this.
It mystifies me that an odorless, colorless gas that constitutes a mere 0.04 % (approx.) of the earth's atmosphere has these magical properties.
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