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To: imardmd1
Hetro sex requires a man and a woman. Thus for any man to have a sex partner there would have to be a woman as that sex partner. An easy woman would still count as a woman in this equation. Thus M must be equal to F.
47 posted on 07/26/2014 5:59:02 AM PDT by logic101.net (How many more children must die on the altar of gun free zones?)
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To: logic101.net
I think you may be missing the point. In Post 14 rbg81 said:

"The average heterosexual man has nine sex partners in a lifetime. The average woman has four."

He is talking about statistics, where, for instance, a monogamous couple may have 5,000 experiences over 50 years, but only one partner each.

Or the wife was a monagamous widow whose first virgin husband married her, went off to war after their honeymoon, and was killed. Then she married another virgin young man, and they lived happily monogamous for 50 more years. Each man had an average of one partner, but she has an average of two partners.

Or take the dairy farmer, in the old days before artificial insemination, who has 30 cows and two bulls, one after the other was butchered. Each of the cows were freshened at different times by each of the bulls. So each bull had an average of 30 partners, but each cow had only two partners.

This is statistics, and we are counting the number of different partners, not the number of experiences. Then apply this kind of thinking to a whole population, over a number of years. It merely means that men seem to be more active, on the average, than women.

Is that making sense to you?

48 posted on 07/26/2014 8:38:05 AM PDT by imardmd1 (Fiat Lux)
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