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To: Swordmaker
I think I've found an error with your application of this Square Cube Law. The example I am going to use is a rod. The rod will be 1 foot long, 1 inch think, and uniform thickness. This rod weighs 2 pounds.

Please describe your square cube law relating to the rod if it were 2 feet long, and 3 feet long, with the same thickness.

257 posted on 04/04/2008 8:36:19 AM PDT by Shryke
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To: Shryke

Re: your rod

The Square Cube Law does not apply. You are proposing a change in only one dimension, length, when the law applies to proportional increases in all dimensions. So long as you are maintaining the same diameter, doubling a
or tripling the length will only double or triple the volume and mass.

If, however, you double your rod in both length and diameter, then the Square Cube Law DOES apply and the area of the rod would be four times greater and the volume would be eight times greater.


262 posted on 04/04/2008 1:19:16 PM PDT by Swordmaker (Remember, the proper pronunciation of IE is "AAAAIIIIIEEEEEEE!)
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To: Shryke

Re: your rod

The Square Cube Law does not apply. You are proposing a change in only one dimension, length, when the law applies to proportional increases in all dimensions. So long as you are maintaining the same diameter, doubling a
or tripling the length will only double or triple the volume and mass.

If, however, you double your rod in both length and diameter, then the Square Cube Law DOES apply and the area of the rod would be four times greater and the volume would be eight times greater.


264 posted on 04/04/2008 1:47:13 PM PDT by Swordmaker (Remember, the proper pronunciation of IE is "AAAAIIIIIEEEEEEE!)
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