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Gravity waves analysis opens 'completely new sense'
spaceref.com ^ | 29 Oct 02 | Washington Univ

Posted on 10/29/2002 10:42:41 AM PST by RightWhale

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To: RightWhale
Obviously these newly discovered waves disprove evolution.
41 posted on 10/29/2002 3:14:55 PM PST by rmmcdaniell
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To: rmmcdaniell
these newly discovered waves disprove evolution

On the contrary, they prove that more local public funds need to be allocated to science education in public schools, and that the Federal Dept of Education should be disbanded.

42 posted on 10/29/2002 3:18:19 PM PST by RightWhale
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To: Barry Goldwater
How do gravity waves escape black holes?

Excellent question. If they have mass (do they?), presumably they can't escape. But obviously a black hole generates (so to speak) a lot of gravity, so ... as I said, an excellent question.

43 posted on 10/29/2002 3:27:49 PM PST by PatrickHenry
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To: oldsalt
Jerry Nadler playing hopscotch would not be detected on the instrumentation needed to detect gravity waves, seismographic equiptment to detect underground nuke tests on the other hand would in fact go nuts
44 posted on 10/29/2002 5:19:29 PM PST by Nebr FAL owner
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To: DugwayDuke
Opinions? It's my opinion that gravity waves are the real cause of my recent weight gain.

The square the sine of gravity waves = gravy waves/2(pork chops x mashed potatoes) + 3(high gravity Steel Reserves).....

And that is the real cause of my recent weight gain.....

45 posted on 10/29/2002 5:28:39 PM PST by freebilly
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To: Barry Goldwater; boris; PatrickHenry
How do gravity waves escape black holes?

We need to be careful to distinguish between the gravitational field and gravitational waves.

The gravitational field is fixed to the black hole. In a nutshell, the gravitational field is the curvature of spacetime caused by the black hole. This curvature is defined everywhere in space, all the way up to the singularity at the center of the black hole; it is even defined inside the event horizon.

Gravitational waves are changes in the gravitational field. If a black hole is accelerated, obviously the field as it exists at some arbitrary point is going to change over time. This is perfectly analogous to the way electromagnetic waves are caused by the acceleration of electrical charges. If you move a charge around, the field associated with that charge will also be moved around. These changes in the field are propagated as a wave.

So in answer to your question, don't think of gravitational waves as radiating outward from a black hole like light from a bulb; rather, think of the gravitational field as being fixed to the black hole, with changes in the motion of the black hole thereby causing changes in the field.

46 posted on 10/29/2002 7:18:53 PM PST by Physicist
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To: PatrickHenry; Barry Goldwater; boris
If they have mass (do they?),

The fact of the inverse square law of gravity demands that gravitational radiation be massless.

presumably they can't escape.

Light is massless, but still that can't escape from a black hole.

You need to think in terms of inertial frames. Event horizons, for example, exist between locations not because there is some physical barrier between them, but because the difference between the inertial frames exceeds the speed of light. Signals from one point to the other can't run fast enough to catch up. It's a question of point-of-view.

Gravitational waves are also a point-of-view thing. The Earth, for example, radiates gravitational waves into space as it whips around the sun. The planet Mars, for example, feels (however feebly) the changing gravitational field of the Earth as it wobbles back and forth in its orbit. We here on Earth, however, can't feel those waves. It doesn't make sense to talk about measuring them as they travel from the center of the Earth on their way to Mars, for the simple fact that the waves don't travel along any such path. From where we're sitting, the gravitational field of the Earth doesn't change at all; there are no such waves to measure, from our point-of-view.

47 posted on 10/29/2002 7:33:06 PM PST by Physicist
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To: RightWhale
What is the speed of propagation of gravity waves?

No higher than the speed of light...unless Einstein was wrong about the fundamental assumption in his relativity theories. Of course if he was then using his theories to predict the shape of gravity waves would seem to not be very productive. Regardless, we are bound to learn something from all this.

48 posted on 10/29/2002 8:52:16 PM PST by El Gato
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To: Jake0001
You seem to have the wrong picture here. Yes the wave will be nearly planer, I least hope so, becuase if it wasn't that would mean something bad happened really near by. But planer waves still have direction of propagation, it's perpindicular to the "plane". Stations not coplaner with the wavefront will still see the wavefront at different times. Those time differences are what allows for determinations of direction. It's the same principle that interferometers work on, although those deal with continuous type waves, rather than a wave front per se. The radar seeker heads and tracking radars in aircraft almost all use a similar interferometer, albeit one with "different" signal processing. We radar folks call it "monopulse", for historical reasons.

49 posted on 10/29/2002 9:05:14 PM PST by El Gato
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Comment #50 Removed by Moderator

To: boris
Have to specify the position of the observor, and remember that its gravity is not just a force in space, but distorts space-time. It is the effect of gravity on time that makes black holes such weird things. But essentially yes, gravity originates from the event horizon. To someone outside, that is where the matter "is".

To an observor outside of and away from the hole, time for the matter falling into the hole slows down as it approaches the event horizon. At the instant the matter reaches the event horizon, "its" time "stops" (again, for an observor away from the hole). All the matter that fell into the hole over its history is "at" the event horizon, not "inside" it, to an observor outside.

It is different for a co-moving reference frame with the matter approaching the horizon. In that reference frame, time continues and it goes right across - while time in the rest of the universe, looking back out, speeds up. Matter crossing an event horizon is "falling out of our space-time", not just going somewhere inside of it.

51 posted on 10/29/2002 10:09:02 PM PST by JasonC
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To: Banger
"gravity is a dimensionless value, but based on the statement that it is the energy of a mass it must be related to mass in some way. There is an inconsistancy..."

Who disputes that gravity is related to mass?

52 posted on 10/29/2002 10:56:43 PM PST by Southack
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To: RightWhale
I don't really disagree with research, but I do disagree with the assertion that it would be of much use in astronomy. Noone could know how frequently these waves are generated.

It is possible that the frequency of waves is low enough that discreet and meaningful wave forms can be measured but what if it is like trying to discern raindrop impacts in a lake with the added complexity of a third dimension? It then becomes a newshour "horror story" about the dangers of existing as the "big one" could come anyday.

Nevertheless I agree it could be very useful. Being able to track gravitational waves could be instrumental in tracking or monitoring local temporal, nuclear or high energy events or activities in addition to enhance our understanding of gravity itself. Further we could use such data to develop artificial gravity and anti-gravity.

53 posted on 10/30/2002 6:22:11 AM PST by Jake0001
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To: GOPJ
"The Hunt for Zero Point"

I just finished it. A good read!

54 posted on 10/30/2002 6:25:11 AM PST by martin gibson
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Comment #55 Removed by Moderator

To: Physicist
When charge moves the electric field is no longer purely coulombic, it now has a motional term (the field actually increases but is still non radiating). Does the gravity field have a corresponding increase toowhen the mass moves? If the mass is accelerated or changes density, it generates a radiation field. Is the radiation field transverse and does it have two components corresponding to electric and magnetic field?

All orbiting charge does not radiate, for example the electron orbiting the atom. What causes the earth to radiate or not radiate when it orbits the sun? What gives the phase quadrature components so it doesn't radiate? Or what are the in phase components to give the radiation? Gravity then must have a wavelength and phase in order to radiate.
56 posted on 10/30/2002 7:15:09 AM PST by Barry Goldwater
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To: Physicist
Has anyone given any thought to what a picture of the sky would look like, "painted" with gravity waves? If the waves were detected and then graphically converted to visible points on the picture, my (non-expert) guess is that it would look pretty much like the night sky does now -- but with some more objects made visible, and "brightness" determined by mass.
57 posted on 10/30/2002 7:39:51 AM PST by PatrickHenry
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To: Barry Goldwater
When charge moves the electric field is no longer purely coulombic, it now has a motional term (the field actually increases but is still non radiating). Does the gravity field have a corresponding increase toowhen the mass moves? If the mass is accelerated or changes density, it generates a radiation field. Is the radiation field transverse and does it have two components corresponding to electric and magnetic field?

I don't completely understand what you're saying, here. (The statement "the field actually increases but is still non radiating" is probably wrong.) There is a gravitomagnetic effect caused by special relativity, but it's pretty subtle because, unlike electromagnetic field, the gravitational field has no dipole moment.

All orbiting charge does not radiate, for example the electron orbiting the atom. What causes the earth to radiate or not radiate when it orbits the sun?

Electrons don't always radiate when they orbit around the atom because they're hard up against the Heisenberg Uncertainty Principle; there's no lower energy state available. There is no such consideration when it comes to the Earth in its orbit. It will radiate gravitational waves continuously.

What gives the phase quadrature components so it doesn't radiate? Or what are the in phase components to give the radiation? Gravity then must have a wavelength and phase in order to radiate.

Again, I don't really understand what you're saying. "Gravity" doesn't have a wavelength, as it's a field. (Geek alert: if gravity can be described by a quantum field theory, then the field could be decomposed into an infinite superposition of quantized virtual gravitational waves, just as the EM field can be described as an infinite series of virtual photons. But that doesn't mean that the field would in any sense have a wavelength.) Gravitational waves--that is, changes in the gravitational field--would have definite wavelengths. It's a whole new spectrum.

The difficulty in detecting gravitational waves is primarily due to their long wavelengths. For example, the gravitational waves radiated by the Earth have a wavelength of exactly one lightyear, because it takes the Earth exactly one year to complete one cycle. Measuring such a wave would require an apparatus of about that scale. LIGO is designed to measure much shorter wavelengths, but the processes that generate gravitational waves with such a short wavelength are few and rare.

58 posted on 10/30/2002 7:59:56 AM PST by Physicist
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To: PatrickHenry
That's a good question, and I've given it some thought myself. I don't know that it would look much like the night sky.

For one thing, the sky looks incredibly different when you look at different frequencies of photons. If you look at visible light, you have the enormous powerhouse of the sun, the band of the galaxy, the Magellanic Clouds, and some very bright stars. If you look at gamma rays, you see an isotropic distribution of point sources. If you look in the far infrared, you see the galaxy, the dipole anisotropy caused by the proper motion of the Earth with respect to the cosmic background radiation, and the cosmic background radiation itself. The x-ray and radio bands show you other things besides.

I would expect that the appearance of the gravitational sky would also be strongly frequency-dependent. Quasars, binary pulsars and galactic clusters would figure prominently, I imagine, as would the rapidly moving stars at the center of our galaxy. The most interesting possibility is that the brightest sources may well be sitting back at the inflationary epoch, far earlier than anything we can see with electromagnetism.

59 posted on 10/30/2002 8:18:24 AM PST by Physicist
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To: Physicist
1. When an electron has velocity the total electric field increases over that of a stationary electron. This total field is non radiating. Check your freshman physics texts. A moving charge is a current, the equation E = J sigma (a form of ohm's law) may help you remember.

2. Hiesenbergs uncertainty principle relates the uncertainty of measurement between a particles momentum and position. A radiation field, by definition is uncoupled from its source. I don't see how the uncertainty principle applies, especially to a field.

3. If Cavendish could measure g with small lead spheres over 100 years ago, certainly today's physicists could produce gravity waves on the orders of tens of kilohertz and measure them. Also as the frequency of the wave increases so would its radiated intensity, making the measurement very easy.

4. Wouldn't gravity waves cause an effect similar to the Lorentz contraction and hence could never be measured?
60 posted on 10/30/2002 1:10:37 PM PST by Barry Goldwater
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