To: cuban leaf
You are appaerently deliberately misstating my assertion.
There is no way to create a delay greater than transmission time without storing the data somewhere for rebroadcast.
Creating packets stores, but not permanently, not usually perceptibly. The delays that are occuring definitely require storage for rebroadcast.
693 posted on
07/01/2013 11:39:06 AM PDT by
editor-surveyor
(Freepers: Not as smart as I'd hoped they'd be)
To: editor-surveyor
To create delay greater than the transmission distance divided by light speed requires recording somewhere.There is no way to create a delay greater than transmission time without storing the data somewhere for rebroadcast.
Surely you see the difference between your TWO assertions.
717 posted on
07/01/2013 11:45:33 AM PDT by
Half Vast Conspiracy
( Because police powers are essential to the public good that abusing them is so offensive.)
To: editor-surveyor
Sorry ES, I did not pay for the full half hour argument. I’m getting back to the topic at hand.
719 posted on
07/01/2013 11:45:41 AM PDT by
cuban leaf
(Were doomed! Details at eleven.)
To: editor-surveyor
Creating packets stores, but not permanently, not usually perceptibly. The delays that are occuring definitely require storage for rebroadcast. That's called buffering, not recording. Recording is when the data is put into a retrievable, "permanent" form for storage.
1,237 posted on
07/01/2013 3:05:46 PM PDT by
MortMan
(Disarming the sheep only emboldens the wolves.)
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