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To: Swordmaker
For example, if the user elects to use a 16 character complex passcode using upper and lower case letters mixed with numbers and symbols, that passcode would be then entangled with the 128 character UUID of the device to construct a 144 character key. The number of possible keys is 144^223.

Either I'm on crack, or they came up with some new permutation math, or that's supposed to be 223^144. ;)

38 posted on 11/03/2015 2:06:27 PM PST by Still Thinking (Freedom is NOT a loophole!)
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To: Still Thinking
Either I'm on crack, or they came up with some new permutation math, or that's supposed to be 223^144. ;)

Brain Fart.

41 posted on 11/03/2015 2:14:31 PM PST by Swordmaker ( This tag line is a Microsoft insult free zone... but if the insults to Mac users continue...)
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