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To: LibWhacker

That doesn’t really answer my question. The equation for velocity is v = d/t or vt = d so as time (t) approaches zero, the distance covered also approaches zero. So it’s not simply a matter of the image being frozen but of the actual movement being frozen, too, at least from the outside frame of reference.


7 posted on 10/13/2008 1:34:02 AM PDT by Question_Assumptions
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To: Question_Assumptions
That doesn’t really answer my question. The equation for velocity is v = d/t or vt = d so as time (t) approaches zero, the distance covered also approaches zero. So it’s not simply a matter of the image being frozen but of the actual movement being frozen, too, at least from the outside frame of reference.

Ahh, Zeno's paradox. The solution (I believe) basically comes down to Plancks Constants, these are units so small that they can't be divided. It is also the idea behind Quantum Mechanics. A singularity would simply be all the Planck constants in a single point.

27 posted on 10/13/2008 6:59:46 AM PDT by LeGrande
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To: Question_Assumptions

Time is not standing still at the event horizon. That is only the ‘barrier’ where light cannot escape the gravitation field.

Your question is covered by Einstein’s Theory of Special Relativity. Time and distance is relative to the observer.

The effects on time and space at the singularity are still up for debate. I’ve seen different ideas from twisting space to create a wormhole to twisting time for time travel or even dimensional travel. Theoretical physicists love this stuff.


33 posted on 10/13/2008 7:31:14 AM PDT by Azeem (The world will look up and shout "Save us!"... And I'll whisper "No.")
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To: Question_Assumptions

The way I understand it, it is not an “image”, it is the actual object. It is not frozen, but slowed down tremendously relative to the outside observer.


35 posted on 10/13/2008 7:51:47 AM PDT by ecomcon
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