...the target is moving? So the shooter is not moving in relation to the shooter? In relation to the discharged round maybe. But how fast is the bullet traveling vs the speed which the earth is rotating.
[Wiki] “At the equator, the circumference of the Earth is 40,070 kilometers, and the day is 24 hours long so the speed is 1670 kilometers/hour ( 1037 miles/hr). This decreases by the cosine of your latitude so that at a latitude of 45 degrees, cos(45) = . 707 and the speed is . 707 x 1670 = 1180 kilometers/hr.”
[Wiki] “The average bullet travels at 2,500 feet per second (around 1,700 mph).”
Theory has it that if you’re standing 500 feet away from a shot you have a tiny bit of a chance to actually dodge the bullet.
I can sort of understand the science behind this Coriolis Effect, but what is low equal to? An inch perhaps?
The calculation you cite assumes the shot being fired and the earth rotation being independent of the trajectory. Not the case. Drive down the highway and toss a tennis ball up 6” and catch it. The ball traveled about 30 yards.
I would think the centrifugal affect of the earths rotation would be more relevant. But with a 3 to 5 second flight time max, the impact would likely be irrelevant and/or too small to calculate considering the effects of wind, elevation, spin drift, temperature variations, altitude, humidity levels, etc.