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To: reg45

There is crushing pressure as you approach the center of the Earth. Think: Marianas Trench.

There is no pressure as you approach Space. Think: astronaut.


34 posted on 04/02/2011 12:48:44 AM PDT by Southack (Media Bias means that Castro won't be punished for Cuban war crimes against Black Angolans in Africa)
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To: Southack

You seem to be confusing mass and density with gravity.

They are not related. The weight of the Ocean above you at the Marianas Trench is the result of mass and density in relation between you and gravity, which is lower at the center of the Earth. Which is why you would be crushed.


38 posted on 04/02/2011 11:06:02 AM PDT by PSYCHO-FREEP (Patriotic by Proxy! (Cause I'm a nutcase and it's someone Else's' fault!....))
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To: Southack
There is crushing pressure as you approach the center of the Earth. Think: Marianas Trench.

You are correct. However the sum of gravitational forces on you (at the center of the earth would still be zero).

Another thought experiment:

A three body problem.

Imagine three bodies in a line. The first (M1) has a mass equal to one half of the earth's mass. The second (M2) has a mass of 100 kg (that could be you). The third (M3) also has a mass equal to one half of the mass of the earth. Imagine each of the three masses were separated by about 10m. The gravitational attraction between M1 and M3 would be very high (what you call a crushing force) while the gravitational attraction between M1 and M2 would be balanced by the gravitational attraction between M3 and M2 (what I call zero gravity). The M2 object would remain in a state of equilibrium between the two much larger masses (M1 and M3) because the vector sum of the gravitational attractions on it would be zero.

48 posted on 04/03/2011 9:53:12 AM PDT by reg45
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