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Former Homosexual Reveals 'Unmitigated Disaster of Gay Marriage'
Charisma News ^ | 7/18/2014 | David Kyle Foster

Posted on 07/24/2014 6:04:58 AM PDT by Gamecock

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To: Ditter

My sister feels the same way. She regrets her choice.


41 posted on 07/24/2014 12:00:06 PM PDT by trisham (Zen is not easy. It takes effort to attain nothingness. And then what do you have? Bupkis.)
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To: Salvation

I wonder why there isn’t? It would be a very good thing.


42 posted on 07/24/2014 12:01:29 PM PDT by trisham (Zen is not easy. It takes effort to attain nothingness. And then what do you have? Bupkis.)
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To: Gamecock
But in so-called "gay marriages" you are guaranteeing that the children will grow up without a mother or father in the home.

Rosie O'Donnell's son told her that he wish he had a father.

43 posted on 07/24/2014 12:15:29 PM PDT by Slyfox (When progressives ignore moral parameters, they also lose the natural gift of common sense.)
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To: Slyfox

another kid which went to my oldest school said he wished he had a father and a mother, but instead got two so called dads.
Yes he runs away time and time , and the poor kid is all screwed up now


44 posted on 07/24/2014 2:47:40 PM PDT by manc (Marriage =1 man + 1 woman,when they say marriage equality then they should support polygamy)
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To: logic101.net
The math doesn’t add up here.

It can. Fewer females with a great many experiences that males. Different distribution statistics displaces the medians, but the area under each distribution is the same.

45 posted on 07/24/2014 2:53:34 PM PDT by imardmd1 (Fiat Lux)
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To: VanDeKoik

The fact that male homosexuals tend to be more promiscuous and lesbians tend to be more into nurturing and bonding show that they’re still all the biological sex they were created as, not some sort of different “gender”.


46 posted on 07/24/2014 10:40:25 PM PDT by Unam Sanctam
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To: imardmd1
Hetro sex requires a man and a woman. Thus for any man to have a sex partner there would have to be a woman as that sex partner. An easy woman would still count as a woman in this equation. Thus M must be equal to F.
47 posted on 07/26/2014 5:59:02 AM PDT by logic101.net (How many more children must die on the altar of gun free zones?)
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To: logic101.net
I think you may be missing the point. In Post 14 rbg81 said:

"The average heterosexual man has nine sex partners in a lifetime. The average woman has four."

He is talking about statistics, where, for instance, a monogamous couple may have 5,000 experiences over 50 years, but only one partner each.

Or the wife was a monagamous widow whose first virgin husband married her, went off to war after their honeymoon, and was killed. Then she married another virgin young man, and they lived happily monogamous for 50 more years. Each man had an average of one partner, but she has an average of two partners.

Or take the dairy farmer, in the old days before artificial insemination, who has 30 cows and two bulls, one after the other was butchered. Each of the cows were freshened at different times by each of the bulls. So each bull had an average of 30 partners, but each cow had only two partners.

This is statistics, and we are counting the number of different partners, not the number of experiences. Then apply this kind of thinking to a whole population, over a number of years. It merely means that men seem to be more active, on the average, than women.

Is that making sense to you?

48 posted on 07/26/2014 8:38:05 AM PDT by imardmd1 (Fiat Lux)
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To: imardmd1

If taking the whole population into account, with the assumption that the number of male and female are equal; then the AVERAGE number of sex partners between the sexes must be equal.

Unless you consider masterbation to be hetro sex than there must be one f for every m. And let’s say most women have 4 partners over their lifetime. There will be a couple that have 50 and they have to be averaged into the equation. Thus M and F must be equal. There cannot be hetro sex w/o a woman.


49 posted on 07/26/2014 5:19:02 PM PDT by logic101.net (How many more children must die on the altar of gun free zones?)
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To: logic101.net

Yes, your point is true with your stipulations, but apparently the statisticians don’t make the same assumptions regarding the size of the m/f split in the population available for engaging. I did not. The m/f constant fixes the numerator, but not the denominator.


50 posted on 07/26/2014 10:09:46 PM PDT by imardmd1 (Fiat Lux)
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