< img src="nameofimage.jpg" height="400" width="550">
Once again, you will take the excess space out of the carets. The height and width numbers will depend on what the reduced size of the image would actually be, whether you had to reduce it by half or two times to make a decent-size image viewable. And the size is in pixels.
I too can leap tall buildings in a single bound but am an idiot with html. I am practicing, but am pretty sure this is not going to post the picture. What am I doing wrong?
I uploaded the picture onto photobucket and then when uploaded right-clicked on my Mac and selected ‘copy link location’ and this is what I got. Seems like too much information. I don’t see an option to ‘hit html code’ like Yaelle mentioned. Thank you very much.
You only need one of height or width. The browser will calculate the other dimension automatically.
Of course, you can take it upon yourself to calc the other dimension. But, if you get it wrong, the image will be distorted.